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Three rods of identical cross-sectional area and made from the same metal form the sides of an isosceles Delta ABC right angled at B. The points A and B are maintained at temperetures T and `sqrt(2)T`, respectively in the steady state. Assuming that only heat conduction takes place, temperature of point C is

A

`(3T)/(sqrt(2)+1)`

B

`(T)/(sqrt(2)+1)`

C

`(T)/(3(sqrt(2)-1))`

D

`(T)/(sqrt(2)-1)`

Text Solution

Verified by Experts

The correct Answer is:
A


As `T_BgtT_A`, heat flows from B to A through both paths BA and BCA.
Rate of heat flow in `BC=` Rate of heat flow in CA
`=(KA(sqrt(2)T-T_C))/(l)=(KA(T_C-T))/(sqrt(2)l)`
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