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2 kg of ice at -20^@C is mixed with 5 kg...

2 kg of ice at `-20^@C` is mixed with 5 kg of water at `20^@C` in an insulating vessel having a negligible heat capacity. Calculate the final mass of water (in kg) remaining in the container.

Text Solution

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Energy with 5 kg of `H_2O` at `20^@C` to become ice at `0^@C`
`E_1=5000xx1xx20=100000cal`
Energy to raise the temperature of 2 kg ice from `-20^@C` to `0^@C`
`E_1=5000xx0.5xx20=20000cal`
`(E_1-E_2)=80000cal` is available to melt ice at `0^@C`.
So only 1000 g or 1 kg of ice would have melt.
So, the amount of water available`1+5=6kg`
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