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An iron wire AB of length 3 m at 0^(@)C ...

An iron wire AB of length `3 m` at `0^(@)C` is stretched between the oppsote walls of a brass casing at `0^(@)C`. The diameter of the wire is `0.6mm`. What extra tension will be set up in the wire when the temperature of the system is rasied to `40^(@)C`?
Given `a_("brass")=18xx10^(-6)//k`
`a_("iron")=12xx10^(-6)//K`
`Y_("iron=21xx10^(10)N//m^(2)`

Text Solution

Verified by Experts


Increase in length of the iron wire
`=Ia Deltat=Ixx12xx10^(-6)xx40`
`=48Ixx10^(-5)m`
Increase in length of the brass tube
`=Ia Deltat=Ixx18xx10^(-6)xx40`
`=72Ixx10^(-5)m`
Since the increase in length of the brass tube is greater than that of the iron wire, the latter will be tightend. Let T be the tension in the wire. Then
Stress `=(T)/(pir^(2))=(T)/(pi(3xx10^(-4))^(2))=(T)/(9pixx10^(-8))`
Strain `=((721-48I)xx10^(-5))/(I)=24xx10^(-5)`
Since stress `=Yxx"Strain", (T)/(9pixx10^(-8))=21xx10^(10)xx24xx10^(-5)`
`7=21xx10^(10)xx9pixx10^(-8)=14.2N`
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