The mass of hydrogen molecule is `3.23 xx 10^(23)` hydrogen molecules strike `2 cm^(2)` of a wall per second at an angle of `45^(@)` with the normal when moving with a speed of `10^(5) cm s^(-1)`, what pressure do they exert on the wall ? Assume collision to be elasitc.

Explanation

To solve the problem, we need to calculate the pressure exerted by hydrogen molecules on a wall when they collide with it at a specific angle and speed. Here’s a step-by-step solution:

### Step 1: Identify Given Values
- Mass of a hydrogen molecule, \( m = 3.32 \times 10^{-27} \) kg
- Number of hydrogen molecules striking the wall per second, \( n = 10^{23} \)
- Area of the wall, \( A = 2 \, \text{cm}^2 = 2 \times 10^{-4} \, \text{m}^2 \)
- Speed of the hydrogen molecules, \( v = 10^5 \, \text{cm/s} = 10^3 \, \text{m/s} \)
- Angle of incidence, \( \theta = 45^\circ \)
...