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Gaseous hydrogen contained initially und...

Gaseous hydrogen contained initially under standard conditions in sealed vessel of volume `V = 5 L` was cooled by `Delta T = 55 K`. Find how much the internal energy of the gas will change and what amount of heat will be lost by the gas.

Text Solution

Verified by Experts

By the first law of thermodynamics
`Delta Q = Delta U + Delta W`
Here `Delta W = =` as the volume remains constant.
`:. Delta Q = Delta U`
Now `Delta U = (m)/(M) (R ) C_(V) (- Delta T)`
`= - (m)/(M) (R )/(gamma - 1) Delta T` `(as C_(V) = (R )/(gamma - 1))`
We have `P_(0)V = (m)/(M) RT_(0)`
`= - (1.013 xx 10^(5) xx (5 xx 10^(-3)) xx 55)/(273 (1.4 - 1)) = - 255 J`
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