How many degress of freedom have the gas molecules, if under standard conditions the gas density is `rho = 1.3 kg//m^3` and velocity of sound propagation o it is `v = 330m//s` ?

Explanation

`v = sqrt((gamma P)/(rho)) implies gamma (v^(2) rho)/(P)`
If `r` = degrees of freedom of rotational motion, them
`gamma + 1 (2)/(r )`
`:.r = (2)/((v^(2) rho)/(p) -1) = (2)/((330^(2) xx 1.3)/(1.015 xx 10^(5) - 1)) = 5`