Equal masses of air are sealed in two vessels, one of volume `V_(0)` and the other of volume `2V_(0)`. If the first vessel is maintained at a temperature `300K` and the other at `600K`, find the ratio of the pressures in the two vessels.

Explanation

As number of moles in the two vessels are equal, we have
`(P_(1) V_(1))/(T_(1)) = (P_(2) V_(2))/(T_(2))`
It is given that `V_(1) = V_(0), V_(2) = 2 V_(0), T_(1) = 300 K` and `T_(2) = 600 K`
Thus we have `(P_(1) V_(0))/(300) = (P_(2) V_(2))/(600)`
or `P_(1) = P_(2)`
or `(P_(1))/(P_(2)) = 1`