The capacity of a vessel is `3 L`. It contains `6 g` oxygen, `8 g` nitrogen and `5 g CO_(2)` mixture at `27^(@)C`, If `R = 8.31 J//mol K`, then the pressure in the vessel in `N//m^(2)` will be (approx.)

Options

A. `5 xx 10^(5)`
B. `5 xx 10^(4)`
C. `10^(6)`
D. `10^(5)`

Answer

A

Explanation

a. By Dalton's law
`P = P_(1) + P_(2) + P_(3) = (mu_(2) RT)/(V) + (mu_(2) RT)/(V) + (mu_(3) RT)/(V)`
`= (RT)/(V) [mu_(1) + mu_(2) + mu_(3)] = (RT)/(V) [(m_(1))/(M_(1)) + (m_(2))/(M_(2)) + (m_(3))/(M_(3))]`
`(8.31 xx 300)/(3 xx 10^(-3)) [(6)/(32) + (8)/(28) + (5)/(44)]`
`= 498 xx 10^(3) = 500 xx 10^(3) = 5 xx 10^(5) N//m^(2)`