Two gases occupy two containers `A` and `B` then gas in `A`, of volume `0.10 m^(3)`, exerts a pressure of `1.40 Mpa` and that in `B`, of volume `0.15 m^(3)`, exerts a pressure `0.7 MP a`. The two containers are joined by a tube of negligible volume and the gases are allowed to intermingle. Then if the temperature remains constant, the final pressure in the container will be (in MPa)

Options

A. 0.7
B. 0.98
C. 1.4
D. 2.1

Answer

B

Explanation

b. As the quantity of gas remains constant, `mu_(A) + mu_(B) = mu`
`(P_(A) V_(A))/(RT) + (P_(B) V_(B))/(RT) = (P (V_(B) + V_(B)))/(RT)`
`P = (P_(A) V_(A) + P_(B) V_(B))/(V_(A) + V_(B)) = (1.4 xx 0.1 + 0.7 xx 0.15)/(0.1 + 0.15)`
`implies P = 0.98 MP a`