A thermodynamic system is taken through the cyclic `PQRSP` process. The net work done by the system is

Options

A. `20 J`
B. `- 20 J`
C. `400 J`
D. `- 374 J`

Answer

B

Explanation

b. Work done by the system = area of shade protion on `P - V` diagram.
`= (300 - 100) 10^(-6) xx (200 - 100) xx 10^(3) = 20 J`
And direction of process is anticlock wise so work done will be negative, i.e., `Delta W = - 20 J`.