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In the given elliptical P-V diagram...

In the given elliptical `P-V` diagram

A

the work done is positive

B

the change in internal energy is non-zero

C

the work done ` = - (pi//4) (P_(2) - P_(1)) (V_(2) - V_(1))`

D

the work done `= pi (V_(1) - V_(2))^(2) - pi (P_(1) - P_(2))^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C

c. The work done = area of `P - V` diagram
`a = (V_(2) - V_(1))/(2), b = (P_(2) - P_(1))/(2)`
`W = - pi ((V_(2) - V_(1))/(2)) ((P_(2) - P_(1))/(2))`
But the cyclic process is anitclockwise, Hence, the wor done is negative
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