Pressure versus temperature graph of an ideal gas as shown in Fig.
Corresponding density `(rho)` versus volume `(V)` graph will be

Options

A.
B.
C.
D.

Answer

B

Explanation

b. Process `AB` is an isothermal process, i.e., `P prop 1//V` and since `rho prop 1//V`, `rho - V` graph will be a rectangular hyperbola. Pressure is increasing, therefore, volume will increase. Process `BC` is an isochoric process. Therefore, `V = ` constant and since `rho = m//V`, density is also constant, i.e.,`rho - V` graph is a dot. Process `CD` is inverse of process `AB` and process `DA` is inverse is `BC`.