The specific heats of argon at constant pressure and constant volume are `525 J//kg` and `315 J//kg`, respectively. Its density at `NTP` will be\

Options

A. `1.77 kg//m^(3)`
B. `0.77 kg//m^(3)`
C. `1.77 g//m^(3)`
D. `0.77 g//m^(3)`

Answer

A

Explanation

a. `C_(P) - C_(v) = (R )/(M) = (PV)/(T M) = (P)/(Td)`
`:. d = (P)/(T(C_(P) - C_(v)))`
`= (1.013 xx 10^(5))/(273 (525 - 315)) = 1.77 Kg//m^(3)`