One mole of an ideal gas is taken from state `A` to state `B` by three different processes (a) `ACB`, (b) `ADB` and (c ) `AEB` as shown in the `P - V` diagram. The heat absorbed by the gas is

Options

A. greater in process (b) than in (a)
B. the least in process (b)
C. the same in (a) and (c )
D. less in (c ) than in (b)

Answer

D

Explanation

d. Heat absorbed by gas in three process is given by
`Q_(ACB) = Delta U + W_(ACB)`
`Q_(ADB) = Delta U`
`Q_(AEB) = Delta U + W_(AEB)`
The change in internal erergy in all the three caese in same and `W_(ACB)` is positive, `W_(AEB)` is negative
Hence `Q_(ACB) gt Q_(ABD) gt Q_(AEB)`