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Two partical A and B execute simple harm...

Two partical `A and B` execute simple harmonic motion according to the equation `y_(1) = 3 sin omega t` and `y_(2) = 4 sin [omega t + (pi//2)] + 3 sin omega t`. Find the phase difference between them.

Text Solution

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Reperesenting a quantity with phase `(omega t)` along the x-axis , quantity with phase `(omega t + phi)` can be reperesented by a voctor making an angle `phi` with the X-axis in the anticlock wise sense and any quanity with phase `(omega t - phi)` can be reperesented by a voctor making an angle `phi` with the X-axis in the anticlock wise sense [as shown in figure

phase difference`= phi = tan ^(-1) (4//3)`
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