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A person normally weighing 60 kg stands ...

A person normally weighing `60 kg` stands on a plateform which oscillates up and down har monically at a frequency `2.0 sec^(-1)` and an amplitude `5.0 cm` . If a machine on the plateform gives the person's weight against time deduce the maximum and minimum reading it will shown, `Take g = 10 m//sec^(2)`.

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To solve the problem, we need to determine the maximum and minimum readings on the weighing machine when a person weighing 60 kg stands on a platform that oscillates harmonically. The platform has a frequency of 2.0 sec^(-1) and an amplitude of 5.0 cm. We will use the concepts of simple harmonic motion (SHM) and the relationship between force, mass, and acceleration. ### Step-by-Step Solution: 1. **Calculate the Weight of the Person:** The weight (W) of the person can be calculated using the formula: \[ W = mg ...
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