A partical is performing SHM of amplitude 'A' and time period 't'. Find the time taken by the partical to go from `0 to A//2`.

Explanation

Let equation of SHMbe `x = A sin omega t`
when `x = 0, t = 0`
when `x = A//2`
`A//2 = A sin omega t`
or ` sin omega t = 1/2`
`omega t = pi//6`
`(2 pi)/(T) t = (pi)/(6)`
`t = T//12`
Hence, time taken is `T//12`, where T is time period of SHM.