A linear harmonic oscillator has a total mechanical energy of `200 J`. Potential energy of it at mean position is `50J`. Find
(i) the maximum kinetic energy,
(ii)the minimum potential energy,
(iii) the potential energy at extreme positions.

Explanation

At mean position , potential energy is minimum and kinetic energy is maximum . Hence.
`U_(min) = 50 J` (at mean position)
And ` K_(max) = E - U_(min) = 200 - 50`
`K_(max) = 150 J` (at mean position)
At exterme positions, kinetic energy is zero and potential energy is maximum
`:. U_(max) = E`
`= 200 J` (at exterme position)