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The perpendicular bisector of the lin...

The perpendicular bisector of the line segment joining P (1, 4) and Q (k, 3) has y-intercept `-4` . Then a possible value of k is (1) 1 (2) 2 (3) `-2` (4) `-4`

Text Solution

Verified by Experts

if two lines are `_|_` then
`m_1 * m_2 = -1`
`m_2 = (4-3)/(1-k) = 1/(1-k)`
`AB _|_ PQ`
`m_1 * m_2 = -1`
`m_1 = -1/m_2 = k-1`
`C= ((1+k)/2, (4+3)/2) = ((1+k)/2, 7/2)`
eqn of line AB is `(y- 7/2)/(x - ((1+k)/2))= k-1`
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Knowledge Check

  • The perpendicular bisector of the line segment joining A(1, 4) and B(t, 3) has y - intercept equal to -4 . Then, the product of all possible values of t is equal to

    A
    1
    B
    2
    C
    `-16`
    D
    `-4`
  • The perpendicular bisector of the line segment joining the points A(1,5) and B(4,6) cuts the Y-axis at

    A
    (0,13)
    B
    (0,-13)
    C
    (0,12)
    D
    (13,0)
  • The equation of the perpendicular bisector of line segment joining points A (4,5) and B (-2,3) is :

    A
    `2x-y+7=0`
    B
    `3x+2y-7=0`
    C
    `3x-y-7=0`
    D
    `3x+y-7=0`
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