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The equation of a wave is y=4 sin[(pi...

The equation of a wave is
`y=4 sin[(pi)/(2)(2t+(1)/(8)x)]`
where y and x are in centimeres and t is in seconds.

A

The amplitude, wavelength velocity, and frequency of wave are `4 cm, 16 cm, 32 cm//s` and 1 Hz, respectively, with wave propagating along-x direction

B

The amplitude, wavelength velocity, and frequency of wave are `4 cm, 32 cm, 16 cm//s` and 0.5 Hz, respectively, with wave propagating along-x direction

C

two positions occupied by the particle at time interval of `0.4` s have a phase difference of `0.4pi` radian.

D

two positions occupied by the particle at seperation of `12 cm s` have a phase difference of `135^(@)`

Text Solution

Verified by Experts

The correct Answer is:
b., c., d.

`y=4 sin[(pi)/(16)(16t+x)]`
compared with `y=a sin[(2pi)/(lambda)(vt+x)]`
Also, `Deltaphi=(2pi)/(lambda)Deltax=(2pi)/(lambda)(vDeltat)`
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