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A pulse is started at a time t=0 along t...

A pulse is started at a time `t=0` along the `+x`direction on a long, taut string. The shape of the pulse at `t=0` is given by function `f(x)` with
here `f` and `x` are in centimeters. The linear mass density of the string is `50 g//m` and it is under a tension of `5N`.
The transverse velocity of the particle at `x=13 cm` and `t=0.015 s` will be

A

`-250 cm//s`

B

`-500 cm//s`

C

`500 cm//s`

D

`-1000 cm//s`

Text Solution

Verified by Experts

The correct Answer is:
a
Transverse velocity `=(dely)/(delt)att=0.015 s, vt=15 cm` As for `x=13 cm`
`(vt-4)ltxltvt`
Therefore, `(dely)/(delt)=-(v)/(4)=-250 cm//s`
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