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A string of length 20 cm and linear mass...

A string of length `20 cm` and linear mass density `0.40 g//cm` is fixed at both ends and is kept under a tension of `16 N.A` wave pulse is produced at `t=0` near an end as shown in figure which travels towards the other end.
when will the string have the shape shown in the figure again? (in `xx10^(-2)s`)

Text Solution

Verified by Experts

The correct Answer is:
2

velocity of the wave,
`V=sqrt(((T)/(mu)))=sqrt(((16xx10^(5)))/(0.4))=2000 cm//s`
time taken to reach to the other end `=(20)/(200)=0.01 s.` time taken to see the pulse again in the original position `=0.01xx2=0.02s`.
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Knowledge Check

  • A string of length 10.0 m and mass 1.25kg stretched with a tension of 50N. If a transverse pulse is created at one end of the string, how long does it take to reach the other end ?

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  • A string of length 0.4 m and mass 10^(-2)kg is tightly clamped at its ends. The tension in the dtring is 1.6 N . Idential wave pulse are produced at one end at equal intervals of time, Deltat . The minimum value of Deltat which allows constructive inetrference successive pulse is

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  • A sting of length 1m and linear mass density 0.01 kg//m is stretched to a tension of 100 N. When both ends of the string are fixed, the three lowest frequencies for standing wave are f_1, f_2 and f_3 . When only one end of the string is fixed, the three lowest frequencies for standing wave are n_1, n_2 and n_3 . Then,

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