A sound differs by 6 dB from a sound of intensity equal to `10(nW)/(cm^2)`. Find the absolute value of intensity of the sound.

Explanation

Intensity level `=log_(10)((I_2)/(I_1))bels=10log((I_2)/(I_1))dB`
here, `I_1=10xx10^-9xx10^4=10^-4(W)/(m^2)`
`6=10log((I_2)/(10^-4))`
or `I_2=(10^(0.6))/(10^4)=(3.98)/(10^4)=4.0xx10^-4(W)/(m^2)`