Does the Doppler effect increase the intensity of wave when its source approaches the observer?

Explanation

When the source approaches the observer, the apparent frequency `(n')` is greater than the actual frequency (n). Therefore, `T'ltT`. If the source emits E units of energy through unit area in one full oscillation of it, then the same amount of energy will pass through unit area in time `T'` Therefore,
`I'=(E)/(T')` and `I=(E)/(T)`
Obviously `I'gtI`. Thus, the intensity of a wave is increased by the Doppler effect when the source approaches the listener.