An observer moves towards a stationary source of sound with a speed `((1)/(5))`th of the speed of sound. The wavelength and frequency of the source emitted are `lamda` and f, respectively. The apparent frequency and wavelength recorded by the observer are, respectively.

Options

A. `1.2f` and `lamda`
B. `f` and `1.2lamda`
C. `0.8` and `0.8lamda`
D. `1.2f` and `1.2lamda`

Answer

A

Explanation

Given that velocity of source `v_s=0` (because it is stationary). Velocity of observer `v_0=((1)/(5))=0.2v` (where v is the velocity of sound.) Actual frequency of source is f and actual wavelength of source is `lamda`. We know from the Doppler's effect that the apparent frequency recorded, when the observer is moving towards the stationary source is given by
`n'=((v+v_0)/(v-v_S))xxn`
`=((v+0.2v)/(v-0))xxn=(1.2v)/(v)xxn=1.2n=1.2f`