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In expressing sound intensity we take 10...

In expressing sound intensity we take `10^(-12)(W)/(m^2)` as the reference level. For ordinary conversation the intensity level is about `10^-6(W)/(m^2)`. Expressed in decibel, this is

A

`10^6`

B

`6`

C

`10^5`

D

`10^10`

Text Solution

Verified by Experts

The correct Answer is:
C
`B=10log_(10)((I)/(I_0))`
`10log_(10)((10^-6)/(10^(-12)))`
`=60dB
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CENGAGE PHYSICS-SOUND WAVES AND DOPPLER EFFECT-Single Correct
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