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When a source moves away from a stationa...

When a source moves away from a stationary observer, the frequency is `(6)/(7)` times the original frequency. Given: speed of sound `=330(m)/(s)` . The speed of the source is

A

`40(m)/(s)`

B

`55(m)/(s)`

C

`330(m)/(s)`

D

`165(m)/(s)`

Text Solution

Verified by Experts

The correct Answer is:
B
`v'=(v)/(v+v)v`
or `(6)/(7)v=(330)/(330+v)v`
or `6xx330+6v=7xx330`
or `6v=330` or `v=55(m)/(s)`
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