A travelling wave has the frequency `upsilon` and the particle displacement amplitude `A`. For the wave the particle velocity amplitude is ………………… and the particle acceleration amplitude is ……………………..

Explanation

If `y = A sin(omegat - kx)`, displacement amplitude `= A`
(Maximum displacement)
Particle velocity,
`v = (dy)/(dt) = A omega cos(omega t - kx)`
Therefore, velocity amplitude `= A omega = A(2 pi v)`
(Maximum velocity)
Particle acceleration,
`A c c = (dv)/(dt) = - A omega^(2) sin(omega tau - kx)`
Therefore, acceleration(maximum acceleration)
amplitude `= A omega^(2) = A(2 pi v)^(2)`.