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A wave equation which gives the displace...

A wave equation which gives the displacement along the y-direction is given by `y = 10^(-4) sin(60t + 2x)` where `x and y` are in meters and `t` is time in seconds. This represents a wave

A

travelling with a velocity of `30 m//s` in the negative x-direction.

B

of wavelength `pi m`

C

of frequency `30//pi Hz`

D

of amplitude `10^-4 m` travelling along the negative x-direction.

Text Solution

Verified by Experts

The correct Answer is:
A, B, C, D

`y = 10^(-4) sin (60 t + 2 x)`. Comparing the given equation with the stansard wave equation travelling in negative x-direction,
`y = a sin(omega t + kx)`
We get amplitude `a = 10^(-4) m`
Also `omega = 60`
`:. 2 pi f = 60 rArr f = (30)/(pi) Hz`
Also, `k = 2`
`rArr (2 pi)/(lamda) = 2 rArr lamda = pi m`
We know that
`v = f lamda = (30)/(pi) xx pi = 30 m//s`.
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Knowledge Check

  • A wave equation which gives the displacement along the y-direction is given by y = 10^(-4) sin(60t + 2x) where x and y are in meters and t is time in secinds. This represents a wave

    A
    (a) travelling with a velocity of `30m//s` in the nrgative x dierction
    B
    (b) of wavelength `pim`
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    ( c ) of frequency `30//pi hertz`
    D
    (d) of amplitude `10^(-4m` travelling along the negative x- direction
  • A wave equation which given the dispplacement along the y-direction is given by , y = 10^(-4)sin (60t +2x) where x and y are in matre and t is time in second. This represents a wave

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    travelling with a velocity of 30 m/s in the negative x- direction
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    of wavelength `(pi)`m
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    of amplitube `10^(-4)`
  • A wave equation which gives the displacement along the Y direction is given by the equation y=10^4sin(60t+2x) , where x and y are in metres and t is time in seconds. This represents a wave

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    of frequency `60//pi Hz`
    D
    Of amplitude `10^4` metre travelling along the positive X direction
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