" (1) "[3x+y=1],[(2k-1)x+(k-1)y=2k+1]quad ([" no lotution ")],[x=1]

If the system of equations 3x+y=1,\ \ (2k-1)x+(k-1)y=2k+1 is inconsistent, then k=

If the system of equations 3x+y=1,(2k-1)x+(k-1)y=2k+1 is inconsistent,then k=(a)1(b)0(c)-1(d)2

The pair of equations 3x+y=1 (2k-1)x+(k-1)y=2k+1 is consistent for what value of k?

( k - 1 ) x - y = 5 , (k + 1 ) x + ( 1 - k ) y = ( 3k + 1 )

For which value of k will the following pair of linear equations have no solution ? 3x + y = 1 , (2k - 1) x + (k- 1) y = 2k + 1.

For what value of k, the system of linear equations x-3y+kz=0, 2x+y+3z=-1, 3x-2y+2z=1 has a unique solution? a) K=1 b)k!=1 c) K!=-1 d) K=0

{:(2x + (k - 2)y = k),(6x + (2k - 1) y = 2k + 5):}

If K is constant such that xy + k = e ^(((x-1)^2)/(2)) satisfies the differential equation x . ( dy )/( dx) = (( x^2 - x-1) y+ (x-1) and y (1) =0 then find the value of K .

If K is constant such that xy + k = e ^(((x-1)^2)/(2)) satisfies the differential equation x . ( dy )/( dx) = (( x^2 - x-1) y+ (x-1) and y (1) =0 then find the value of K .