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The area of the plane region bounded by ...

The area of the plane region bounded by the curves `x""+""2y^2=""0` and `x""+""3y^2=""1` is equal to (1) `5/3` (2) `1/3` (3) `2/3` (4) `4/3`

A

`(4)/(3)` sq units

B

`(5)/(3)` sq unit

C

`(1)/(3)` sq unit

D

`(2)/(3)` sq unit

Text Solution

Verified by Experts

On solving the given curves, we get
`y=pm1 and x=-2`
`therefore` Intersection points are (-2,1) and (-2,-1)
`therefore` Required area `=|int_(-1)^(1)(1-3y^(2)-2y^(2))dy|`

`=|2int_(0)^(1)(1-y^(2))dy|=|2[y-(y^(3))/(3)]_(0)^(1)|=(4)/(3)` sq units
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