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Let vec a , vec b , vec c be the positi...

Let ` vec a , vec b , vec c` be the position vectors of three distinct points A, B, C. If there exist scalars x, y, z (not all zero) such that `x vec a+y vec b+z vec c=0a n dx+y+z=0,` then show that `A ,Ba n dC` lie on a line.

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Three points with position vectors vec(a), vec(b), vec(c ) will be collinear if there exist scalars x, y, z such that

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Statement -1 : If a transversal cuts the sides OL, OM and diagonal ON of a parallelogram at A, B, C respectively, then (OL)/(OA) + (OM)/(OB) =(ON)/(OC) Statement -2 : Three points with position vectors veca , vec b , vec c are collinear iff there exist scalars x, y, z not all zero such that x vec a + y vec b +z vec c = vec 0, " where " x +y + z=0.

Statement -1 : If a transversal cuts the sides OL, OM and diagonal ON of a parallelogram at A, B, C respectively, then (OL)/(OA) + (OM)/(OB) =(ON)/(OC) Statement -2 : Three points with position vectors veca , vec b , vec c are collinear iff there exist scalars x, y, z not all zero such that x vec a + y vec b +z vec c = vec 0, " where " x +y + z=0.