x=2cos theta-cos2 theta,y=2sin theta-sin2 theta k

If x=cos theta-cos2 theta,y=sin theta-sin2 theta then (dy)/(dx) is

If x=2cos theta -cos 2theta ,y=2sin theta -sin 2theta ,then (dy)/(dx) =

If x=2cos theta-cos2 theta and y=2sin theta-sin2 theta then prove that (dy)/(dx)=tan((3 theta)/(2))

If x=2cos theta-cos2 theta and y=2sin theta-sin2 theta, prove that (dy)/(dx)=tan((3 theta)/(2))

If =2cos theta-cos2 theta and y=2sin theta-sin2 theta Prove that (dy)/(dx)=tan((3 theta)/(2))

If x=cos theta-cos 2theta and y=sin theta-sin2theta , then find (dy)/(dx) .

If x=2cos theta -cos2 theta and y=2sin theta -sin2 theta , find (d^2y)/(dx^2) at theta=pi/2 .

x = cos theta - cos 2 theta, y = sin theta - sin 2 theta . then find dy/dx

If x = 2 cos theta - cos 2 theta, y = 2 sin theta - sin 2 theta, find dy/dx at theta = pi/2

Evaluate the following determinants: (b) |(cos theta, -sin theta),(sin theta, cos theta)| = cos theta (cos theta) - sin theta(-sin theta) = cos^(2) theta + sin^(2) theta = 1