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The ionisation potential of hydrogen is ...

The ionisation potential of hydrogen is `13.60 eV`. Calculate the energy required to produce one mole of `H^(o+)` ion `(1 eV = 96.3 kJ mol^(-1))`.

Text Solution

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The ionisation potential may be represented as
`H_((g)) + 13.60 eV rarr H_((g))^(o+) + e^(-)`
We know `1 eV = 96.3 kJ mol^(-1)`
`13.60 eV = 96.3 xx 13.60 = 1309.68 kJ`
Thus, energy per mol `= 1309.68 kJ`
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