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The electron gain enthalpy of chlorine 3...

The electron gain enthalpy of chlorine `3.7 eV`. How much energy in `kJ` and `kcal` is released when `1 g` of chlorine is converted completely to `Cl^(o-)` ion in the gaseous state. `(1 eV = 96.3 kJ mol^(-1))`

Text Solution

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The electron gain enthalpy in `kJ` is represented as
`Cl_((g)) + e^(-) rarr Cl_((g))^(ɵ) + 3.7 eV`
Now, `1 eV atom^(-1) = 96.3 kJ mol^(-1)`
`:. 3.7 eV = 3.7 eV xx 96.3 kJ mol^(-1)`
Energy released when `35.5 g (1 "mole")` of chlorine is completely converted to `Cl_((g))^(ɵ)` ion `= 3.7 xx 96.3 kJ`
Energy released when `1 g` of chlorine is completely converted to `Cl_((g))^(ɵ)` ion `= (3.7 xx 96.3)/(35.5) = 10.04 kJ`
b. `Delta_(eg)H^(ɵ)` in kcal
`(1 eV = 23.06 kcal mol^(-1))`
`:. Delta_(eg)H^(ɵ) = (3.7 xx 23.06)/(35.5) = 2.4 kcal`
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