The correct order of relative basic character of `NaOH, Mg(OH)_(2)` and `Al(OH)_(3)` is

Options

A. `Al(OH)_(3) gt Mg(OH)_(2) gt NaOH`
B. `Mg(OH)_(2) gt NaOH gt Al(OH)_(3)`
C. `NaOH gt Mg(OH)_(2) gt Al(OH)_(3)`
D. `Al(OH)_(3) gt NaOH gt Mg (OH)_(2)`

Explanation

To determine the correct order of relative basic character of NaOH, Mg(OH)₂, and Al(OH)₃, we can follow these steps:

### Step 1: Understand the nature of the hydroxides
- Sodium hydroxide (NaOH), magnesium hydroxide (Mg(OH)₂), and aluminum hydroxide (Al(OH)₃) are all metal hydroxides.
- Basicity refers to the ability of a substance to accept protons (H⁺ ions) or donate hydroxide ions (OH⁻).

### Step 2: Analyze the position of elements in the periodic table
- Sodium (Na) is an alkali metal located in Group 1 of the periodic table.
- Magnesium (Mg) is an alkaline earth metal located in Group 2.
- Aluminum (Al) is a post-transition metal located in Group 13.

### Step 3: Compare the basicity of the hydroxides
- Basicity generally decreases as we move from left to right across a period in the periodic table. This is due to the increasing electronegativity of the elements, which makes it harder for them to donate hydroxide ions.
- Sodium hydroxide (NaOH) is expected to be the most basic because sodium is further left in the periodic table compared to magnesium and aluminum.
- Magnesium hydroxide (Mg(OH)₂) is less basic than sodium hydroxide but more basic than aluminum hydroxide.
- Aluminum hydroxide (Al(OH)₃) is amphoteric, meaning it can act as both an acid and a base, but it is generally less basic than both NaOH and Mg(OH)₂.

### Step 4: Establish the order of basicity
Based on the analysis:
- NaOH > Mg(OH)₂ > Al(OH)₃

### Conclusion
The correct order of relative basic character of NaOH, Mg(OH)₂, and Al(OH)₃ is:
**NaOH > Mg(OH)₂ > Al(OH)₃**