The inner electrons are shielded to a ""...

The inner electrons are shielded to a `"______"` extent than the outer electrons.

Text Solution

Verified by Experts

The correct Answer is:

Lesser

Topper's Solved these Questions

PERIODIC CLASSIFICATION OF ELEMENTS AND GENERAL INORGANIC CHEMISTRY
CENGAGE CHEMISTRY|Exercise Exercises (True/False)|10 Videos
PERIODIC CLASSIFICATION OF ELEMENTS AND GENERAL INORGANIC CHEMISTRY
CENGAGE CHEMISTRY|Exercise Exercises (Archives ) Multiple Correct|3 Videos
PERIODIC CLASSIFICATION OF ELEMENTS AND GENERAL INORGANIC CHEMISTRY
CENGAGE CHEMISTRY|Exercise Exercises (Integer)|13 Videos
P-BLOCK GROUP 14 - CARBON FAMILY
CENGAGE CHEMISTRY|Exercise Exercises Archives (Subjective)|9 Videos
PURIFICATION OF ORGANIC COMPOUNDS AND QUALITATIVE AND QUANTITATIVE ANALYSIS
CENGAGE CHEMISTRY|Exercise Assertion Reasoning Type|5 Videos

Similar Questions

Explore conceptually related problems

Statement-1: Boron has a smaller first ionisation enthalpy than beryllium. Statement-2: The penetration of a 2s electron to the nucleus is more than the 2p electron hence 2p electron is more shielded by the inner core of electrons than the 2s electrons.

Assertion: Boron has a smaller first ionisation enthalpy than beryllium. Reason: The penetration of a 2s electron to the nucleus is more than the 2p electron, hence 2p electorn is more shielded by the inner core of electrons than the 2s electrons.

B has a smaller first ionization enthalpy than Be. Consider the following statements (i) it is easier to remove 2p electron than 2s electron (ii) 2p electron of B is more shielded from the nucleus by the inner core of electrons than the 2s electrons of Be (iii) 2s electron has more penetration power than 2p electron (iv) atomic radius of B is more than Be (atomic number B= 5, Be = 4) The correct statements are

Al has a smaller first ionization enthalpy than Mg. Consider the following statements : I. It is easier to remove 3p electron than 3s electron . II . 3p electron of Al is more shielded from the nucleus by the inner coreof electron than the 3s electrons of Mg III. 3s electron hasmore penetration power than 3p electron IV. Atomic radius of Al is more than Mg ( atomic number Al=13, Mg = 12 ) The correct statements are :

The inner shells of electrons are completely filled in

The reducing effect of the nuclear charge by the inner electrons for on outer electron is termed aas shielding (or screening). As a result of shielding, the outer electrons in an atom always experience less nnuclear charge than the actual nuclear charge Z. The effective nuclear charge (Z^(**)) as experienced by an electron is then obtained by subtracting the total shielding contributions from alll the other electrons (i.e., except the one under consideration) from the actual nuclear charge. Z^(**)=Z-sigma Where sigma =sum of the shielding contributions. The rules for estimating contributions to sigma are as follows (Slater's rule) Contribution to shielding by each electron is : |{:("Electron","All Higher","Same","Group","Group"le),("Grpoup","Group","Group",n-1,n-2),(1s," "0,0.30,-,-),((ns,sp)," "0,0.35,0.85,1.00),((nd)or(nf)," "0,0.35,1.00,1.00):}| According to Slater's treatment, the energy of an electron in nth shell of an atom having atomic number Z is given by the empirical equation E=-13.6((Z^(**))/(n))^(2)eV Z^(**) = effective nuclear charge Atomic radii of the noble gases are larger than the precedent elements of the same periods because:

The reducing effect of the nuclear charge by the inner electrons for on outer electron is termed aas shielding (or screening). As a result of shielding, the outer electrons in an atom always experience less nnuclear charge than the actual nuclear charge Z. The effective nuclear charge (Z^(**)) as experienced by an electron is then obtained by subtracting the total shielding contributions from alll the other electrons (i.e., except the one under consideration) from the actual nuclear charge. Z^(**)=Z-sigma Where sigma =sum of the shielding contributions. The rules for estimating contributions to sigma are as follows (Slater's rule) Contribution to shielding by each electron is : |{:("Electron","All Higher","Same","Group","Group"le),("Grpoup","Group","Group",n-1,n-2),(1s," "0,0.30,-,-),((ns,sp)," "0,0.35,0.85,1.00),((nd)or(nf)," "0,0.35,1.00,1.00):}| According to Slater's treatment, the energy of an electron in nth shell of an atom having atomic number Z is given by the empirical equation E=-13.6((Z^(**))/(n))^(2)eV Z^(**) = effective nuclear charge Among the following, which electron of Fe atom experience minimum attraction from nucleus? (Atomic number of Fe = 26)

The reducing effect of the nuclear charge by the inner electrons for on outer electron is termed aas shielding (or screening). As a result of shielding, the outer electrons in an atom always experience less nnuclear charge than the actual nuclear charge Z. The effective nuclear charge (Z^(**)) as experienced by an electron is then obtained by subtracting the total shielding contributions from alll the other electrons (i.e., except the one under consideration) from the actual nuclear charge. Z^(**)=Z-sigma Where sigma =sum of the shielding contributions. The rules for estimating contributions to sigma are as follows (Slater's rule) Contribution to shielding by each electron is : |{:("Electron","All Higher","Same","Group","Group"le),("Grpoup","Group","Group",n-1,n-2),(1s," "0,0.30,-,-),((ns,sp)," "0,0.35,0.85,1.00),((nd)or(nf)," "0,0.35,1.00,1.00):}| According to Slater's treatment, the energy of an electron in nth shell of an atom having atomic number Z is given by the empirical equation E=-13.6((Z^(**))/(n))^(2)eV Z^(**) = effective nuclear charge The size of isoelectronic species -F^(-),Na^(+) and Mg^(2+) is effected by:

CENGAGE CHEMISTRY-PERIODIC CLASSIFICATION OF ELEMENTS AND GENERAL INORGANIC CHEMISTRY-Exercises (Fill In The Blanks)

IUPAC name for the element with Z = 117 is "" and its symbol is " ".
Text Solution
|
In the long form of the perodic table, physical and chemical propertie...
Text Solution
|
The property used by Mendeleev to classify the elements in his periodi...
Text Solution
|
The elements which constitute 5f-block are called " " with atomic numb...
Text Solution
|
Elements of s and p blocks are collectively called ""
Text Solution
|
The group all members of which are in gaseous state under ordinary con...
Text Solution
|
Lather Meyer drew a graph showing the relation between atomic "" and ...
Text Solution
|
Ionic radii "" with increases in atomic number in a period and "" in...
Text Solution
|
The electron gain enthalpy of oxygen is "" that of sulphur.
Text Solution
|
On Mulliken scale the average of IP and EA is known as "" .
Text Solution
|
On the Pauling's EN scale, the element next to F is ""
Text Solution
|
The IE of Be is "" than that of B.
Text Solution
|
The bond angle in SO(4)^(2-) ion is "" .
Text Solution
|
The angle between two covalent bonds is maximum for (CH(4), H(2)O, CO(...
Text Solution
|
Second element of group 1 shows diagonal relationship with the first e...
Text Solution
|
The EN of the elements C, N, Si and P increases in the order of "" .
Text Solution
|
The decreasing ordr IE for elements Li, Be, C B is "" .
Text Solution
|
The type of magnetism exhibited by [Mn(H(2)O)(6)]^(2+) ion is "" .
Text Solution
|
Among the ions Cl^(ɵ), S^(2-) and Na^(o+), the largest ion is "" .
Text Solution
|
The inner electrons are shielded to a "" extent than the outer electro...
Text Solution
|