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Which statement is/are correct(more than...

Which statement is/are correct(more than one correct) ?
(a) In aqueous solution `A1` gives hydrated ions `[A1(H_(2)O)_(6)]^(3+)`
(b) Most of aluminium compounds are covalent because formation of `A1^(3+)` requires much more energy `(=5138 kJ mo1^(-1))` which is not available ordinarily
(c ) In aqueous solution `A1` forms hydrated ions becuse og high (negative) heat of hydration of `A1^(3+)` compensates the high `IE_(3)` of `A1`
(d) Magnitude of hydration energy of `A1^(3+)lt IE_(3)` of `A1` .

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To determine which statements about aluminum (Al) and its compounds are correct, we will analyze each statement one by one. ### Step-by-Step Solution: 1. **Statement (a)**: In aqueous solution, Al gives hydrated ions \([Al(H_2O)_6]^{3+}\). - **Analysis**: Aluminum typically forms a hexaaqua complex in aqueous solution due to its +3 oxidation state. The small size of Al³⁺ allows it to attract water molecules, forming a stable octahedral complex. - **Conclusion**: This statement is **correct**. 2. **Statement (b)**: Most of aluminum compounds are covalent because formation of Al³⁺ requires much more energy (=5138 kJ mol⁻¹) which is not available ordinarily. - **Analysis**: The formation of Al³⁺ from Al requires a significant amount of energy (5138 kJ/mol), indicating that it is energetically unfavorable under normal conditions. This leads to the formation of covalent compounds instead of ionic ones. - **Conclusion**: This statement is **correct**. 3. **Statement (c)**: In aqueous solution, Al forms hydrated ions because of high (negative) heat of hydration of Al³⁺ compensates the high IE₃ of Al. - **Analysis**: The heat of hydration for Al³⁺ is indeed highly negative, which means that the energy released when Al³⁺ ions are hydrated compensates for the energy required to remove the third electron (IE₃). This allows Al³⁺ to exist stably in solution. - **Conclusion**: This statement is **correct**. 4. **Statement (d)**: Magnitude of hydration energy of Al³⁺ < IE₃ of Al. - **Analysis**: This statement is incorrect. The hydration energy of Al³⁺ is actually greater than the ionization energy (IE₃) of Al. The high hydration energy is what allows Al³⁺ to exist in solution despite the high ionization energy. - **Conclusion**: This statement is **incorrect**. ### Final Answer: The correct statements are (a), (b), and (c). ---

To determine which statements about aluminum (Al) and its compounds are correct, we will analyze each statement one by one. ### Step-by-Step Solution: 1. **Statement (a)**: In aqueous solution, Al gives hydrated ions \([Al(H_2O)_6]^{3+}\). - **Analysis**: Aluminum typically forms a hexaaqua complex in aqueous solution due to its +3 oxidation state. The small size of Al³⁺ allows it to attract water molecules, forming a stable octahedral complex. - **Conclusion**: This statement is **correct**. ...
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