Compare the bond lenth of `O-O` in the following molecules
(a) `KO_(2)` , (b) `O_(2)[AsF_(6)]`
(c ) `O_(2)` , (d) `Na_(2)O_(2)` .

Explanation

`KO_(2)` has `O_(2)^(Θ)` (superoxide ion) Bond order = 1.5
(b) `O_(2)[AsF_(6)]` has `O_(2)^(o+)` , Bond order =25
(c ) `O_(2)` bond order =2
(d) `Na_(2)O_(2)` has `O_(2)^(2-)` (peroxide ion), Bond order =1 Higher is the `BO` smaller is the bond lenght Hence order of bond lenght is
`O_(2)^(o+) ltO_(2)ltO_(2)^(Θ) ltO_(2)^(2-)` .