The single and multiple bond radii of some elements given in the following table Calculate the bond lengths in
(a) `SCI_(2)`
(b) `NH_(3)`
(c ) `CH_(2)CI_(2)`
(d) `HOCI`
(e) `HCN`
(f )`H_(3)PO_(4)`
(g) `CH_(3)NH_(2)`
.

Explanation

Covalent bond radii from Table 2.24 are merely added
(a) `(1.04 + 0.99) = 2.03Å`
(b) `(0.70 + 0.28) = 0.98 Å`
(c ) `C -H = (0.77 + 0.28) = 1.05Å`
`C -CI = (0.77 + 0.99) = 1.76Å`
(d) `H -O = 0.94 Å`
` O -CI = 1.65 Å`
(e) `H -CI = 1.05Å`
`(C -= N) = (0.61 + 0.55) = 1.16 Å`
(f) `H -O 0.94 Å`
`O - P =1.76 Å`
(g) `C -H = 1.05 Å`
`C -H = 1.74 A N -H = 0.98 Å` .