Arrange the following in decreasing order of dipole moment
(a) Toluene (2) m-Dichlorobenzene
(3) o-Dichlorobenzene (4) p-Dichlorobenzene
(b) BF_(3) (2) `H_(2)S` (3) `H_(2)O`
(c ) cis-1 Chloropropene
(2) Trans -1 -Chloropropene
(3) 1,1-Dichloroethene .

Explanation

`(C gt B gt A gt D)` Smaller is the angle `Q` more is the mu
(b) `H_(2) O gt H_(2)S gt BF_(3) (C gt B gt A) BF_(3)` has `mu=0` because of symmetry `H_(2)S` has lover mu than that of `H_(2)O` because of much lower bond polarity of `H-S` bond as compared to `O-H` bond Hence the order is as givne above `mu_("net")` of `C gt B gt A` In `C` angle between two CI-atoms is small so more is the valuse of mu

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