The molecule having one unpaired electrons is .

Options

A. `O_(2)`
B. `CN^(Θ)`
C. `NO`
D. `CO`

Explanation

The electronic cofiguration of each species according to `MO` theory
(a) `O_(2) (8+8 =6e^(-))implies(sigma1s^(2)) (sigma^(**)1s^(2))(sigma2s^(2))(sigma^(**)2s^(2))`
`(sigma 2p_(z)^(2)) (pi 2p_(x)^(2) =pi 2p_(y)^(2))`
`(pi^(**)2p_(x)^(1))(pi^(**)2p_(y)^(1))`
(Two unpaired `e^(-')s`)
(b) `CN^(Θ) (6 +7 + 1 =14e^(-)) implies (sigma 1s^(2)) (sigma^(**)1s^(2)) (sigma2s^(2))`
`(sigma ^(**)2s^(2)) (sigma2p_(z)^(2))` (No unpaired `e^(-')s`)
(c ) `NO (7 +8 = 15e^(-')) implies (sigma 1s^(2)) (sigam ^(**)1s^(2)) (sigma 2s^(2)) (sigma^(**)2s^(2))`
`(sigma 2p_(z)^(2)) (pi2p_(x)^(2)) (pi2p_(y)^(2))(pi^(**)2p_(x)^(1))`
`(sigma 2p_(z)^(2)) (pi2p_(x)^(2))(pi2p_(y)^(2))(pi^(**)2p_(x)^(1))`
(one unapired` e^(-))`
Hence, answer is (c)
(d) `CO (6 +8 = 14 e^(-))` Similar to that of `CN^(Θ)` .