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The bond angles of NH(3),NH(4)^(o+) and ...

The bond angles of `NH_(3),NH_(4)^(o+)` and `overset(Theta)(NH_(2)` are in the order .

A

`NH_(2)^(Theta) gt NH_(3) gt overset(o+)NH_(4)`

B

`overset(o+)NH_(4) gt NH_(3) gt overset(Theta)NH_(2)`

C

`NH_(3) gtoverset(Theta)NH_(2) gt overset(o+)NH_(4)`

D

`NH_(3) gt overset(o+)NH_(4) gt overset(Theta)NH_(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
`overset(o+)NH_(4)implies sp^(3)` hybridised with no lp of `e^(-')s` so shape is `TH` and bond angle ` =109^(@) 28`
(2) `overset(..)NH_(3) implies sp^(3)` hybridised and is pyramidal in shape with one lp of `e^(-') s` so due to lp-dp ad bp-bp respulsion bond angle decreases to `107^(@)`
`:overset(Theta)overset(..)NH_(2)` implies Hybridisation ` =(1)/(2) (5 +2 +1) = 4 = sp^(3)`
`:overset(Theta)overset(..)NH_(2)` is `sp^(3)` hybridised with two lp of `e^(-')s` so due to lp - lp, lp-bp and `bp -bp` repusion bond angle is further decreases to `104. 5^(@)` (like `H_(2)overset(..)O:` ) and have V-shape .
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