Bond order of `SO_(2)` is .

Options

A. `1.5`
B. `1.33`
C. `2.0`
D. `2.5`

Explanation

To find the bond order of sulfur dioxide (SO₂), we can follow these steps:

### Step 1: Understand the structure of SO₂
Sulfur dioxide (SO₂) consists of one sulfur atom and two oxygen atoms. The molecular structure can be represented as O=S=O, indicating that there are double bonds between sulfur and each oxygen atom.

### Step 2: Identify the types of bonds
In SO₂, we have:
- Sigma (σ) bonds: These are single bonds formed by the head-on overlap of atomic orbitals.
- Pi (π) bonds: These are formed by the side-to-side overlap of p orbitals.

For SO₂:
- There are 2 σ bonds (one for each S=O bond).
- There is 1 π bond (also for each S=O bond, since each double bond consists of one σ bond and one π bond).

### Step 3: Calculate the bond order
The bond order can be calculated using the formula:
\[ \text{Bond Order} = \frac{( \text{Number of σ bonds} + \text{Number of π bonds})}{\text{Number of bonds}} \]

In SO₂:
- Number of σ bonds = 2
- Number of π bonds = 1
- Total number of bonds = 2 (since each S=O bond is counted as one bond)

Now, substituting the values into the formula:
\[ \text{Bond Order} = \frac{(2 + 1)}{2} = \frac{3}{2} = 1.5 \]

### Final Answer
The bond order of SO₂ is 1.5.

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