Assertion `O_(2)` and `N_(2)^(2-)` have same number of electrons and same molecualar orbital configuration
Reasoning `O_(2)` and `N_(2)^(2-)` have the same bond order .

Options

A. If both `(A)` and `(R )` are correct and `(R )` is the correct explanation of `(A)`
B. If both `(A)` and `(R )` are correct and `(R )` is the correct explanation of `(A)`
C. If `(A)` is correct but `(R )` is incorrect
D. If `(A)` is incorrect but `(R )` is correct

Explanation

To solve the question, we need to analyze the assertion and reasoning provided regarding the molecular orbital configurations and bond orders of \(O_2\) and \(N_2^{2-}\).

### Step-by-Step Solution:

1. **Determine the Electron Configuration of \(O_2\)**:
- Oxygen (O) has an atomic number of 8, which means each oxygen atom has 8 electrons. Therefore, \(O_2\) has a total of \(8 + 8 = 16\) electrons.
- The molecular orbital configuration for \(O_2\) is:
\[ \sigma_{1s}^2 \sigma_{1s}^*^2 \sigma_{2s}^2 \sigma_{2s}^*^2 \sigma_{2p_z}^2 \pi_{2p_x}^2 \pi_{2p_y}^2 \pi_{2p_x}^*^1 \pi_{2p_y}^*^1 \]
- This results in a bond order of:
\[ \text{Bond Order} = \frac{(8 \text{ bonding electrons} - 4 \text{ antibonding electrons})}{2} = \frac{4}{2} = 2 \]

2. **Determine the Electron Configuration of \(N_2^{2-}\)**:
- Nitrogen (N) has an atomic number of 7, so each nitrogen atom has 7 electrons. Therefore, \(N_2\) has a total of \(7 + 7 = 14\) electrons. The \(N_2^{2-}\) ion has 2 additional electrons, giving it \(14 + 2 = 16\) electrons.
- The molecular orbital configuration for \(N_2^{2-}\) is:
\[ \sigma_{1s}^2 \sigma_{1s}^*^2 \sigma_{2s}^2 \sigma_{2s}^*^2 \sigma_{2p_z}^2 \pi_{2p_x}^2 \pi_{2p_y}^2 \pi_{2p_x}^*^1 \pi_{2p_y}^*^1 \]
- This also results in a bond order of:
\[ \text{Bond Order} = \frac{(8 \text{ bonding electrons} - 4 \text{ antibonding electrons})}{2} = \frac{4}{2} = 2 \]

3. **Compare the Molecular Orbital Configurations**:
- Both \(O_2\) and \(N_2^{2-}\) have the same total number of electrons (16) and the same molecular orbital configuration.
- However, the assertion that they have the same bond order is incorrect. \(O_2\) has a bond order of 2, while \(N_2^{2-}\) also has a bond order of 2.

4. **Conclusion**:
- The assertion is **true**: \(O_2\) and \(N_2^{2-}\) have the same number of electrons and the same molecular orbital configuration.
- The reasoning is **false**: While both have the same bond order, the bond order for \(O_2\) is 2, and for \(N_2^{2-}\) is also 2, but the reasoning does not correctly support the assertion.

### Final Answer:
- Assertion (A) is correct, and Reasoning (R) is incorrect. Therefore, the answer is **D**.