Bond order for `N_(2)^(o+)` and `N_(2)^(Theta)` are same (i.e2.5)
Reasoning `N_(2)^(o+)` is more stable than `N_(2)^(Theta)` .

Options

A. If both `(A)` and `(R )` are correct and `(R )` is the correct explanation of `(A)`
B. If both `(A)` and `(R )` are correct and `(R )` is the correct explanation of `(A)`
C. If `(A)` is correct but `(R )` is incorrect
D. If `(A)` is incorrect but `(R )` is correct

Answer

B

Explanation

Bond order of `N_(2)^(o+)` and `N_(2)^(Theta)` is same but number of bonding `e^(-)s (N_(b))` are more in `N_(2)^(o+)` whereas number of antibonding `e^(-')s` are more in`N_(2)^(Theta)` Hence both `A` and `R` are correct but `R` is not the correct explanation of `A` .