Assertion `BF_(3)` has greater dipole momnet than `H_(2)S`
Reasoning Fluorine is more electronegative than sulphur .

Options

A. If both `(A)` and `(R )` are correct and `(R )` is the correct explanation of `(A)`
B. If both `(A)` and `(R )` are correct and `(R )` is the correct explanation of `(A)`
C. If `(A)` is correct but `(R )` is incorrect
D. If `(A)` is incorrect but `(R )` is correct

Answer

D

Explanation

Correct `(A) : BF_(3)` is `sp^(2)` hybridised and is triangular planar therefore `mu = 0 H_(2) overset(..)S:` is `sp^(3)` hybridised and is bent molecule therefore `mu ne 0` Therefore `mu gt H_(2) Sgtmu BF_(3)` .