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How many of the following compounds have...

How many of the following compounds have `(p pi-dpi)` multiple bonds
(i) `SO_(2)` (ii) `SO_(3)` (iii) `H SO_(4)^(Theta)` (iv) `SO_(4)^(2-)`
(v) `SO_(3)^(3-)` (vi) `H SO_(3)^(Theta)` .

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To determine how many of the given compounds have `(p pi-d pi)` multiple bonds, we need to analyze each compound one by one. ### Step-by-Step Solution: 1. **Identify the Compounds**: We have the following compounds to analyze: - (i) `SO2` - (ii) `SO3` - (iii) `HSO4^-` - (iv) `SO4^(2-)` - (v) `SO3^(3-)` - (vi) `HSO3^-` 2. **Analyze `SO2`**: - In `SO2`, sulfur forms two double bonds with oxygen. The bond type here includes a `p pi-d pi` bond because sulfur has available d orbitals and can overlap with the p orbitals of oxygen. - **Conclusion**: `SO2` has `p pi-d pi` bonds. 3. **Analyze `SO3`**: - In `SO3`, sulfur forms three double bonds with oxygen. This involves two `p pi-d pi` bonds and one `p pi-p pi` bond. - **Conclusion**: `SO3` has `p pi-d pi` bonds. 4. **Analyze `HSO4^-`**: - In `HSO4^-`, the sulfur is bonded to four oxygen atoms, with one of them being a double bond. The structure can be considered similar to `SO4^(2-)` where the sulfur is surrounded by four oxygen atoms. - **Conclusion**: `HSO4^-` has `p pi-d pi` bonds. 5. **Analyze `SO4^(2-)`**: - In `SO4^(2-)`, sulfur forms four bonds with oxygen, with two of them being double bonds. This structure also allows for `p pi-d pi` bonding. - **Conclusion**: `SO4^(2-)` has `p pi-d pi` bonds. 6. **Analyze `SO3^(3-)`**: - In `SO3^(3-)`, sulfur forms three bonds with oxygen, but the bonding does not involve `p pi-d pi` interactions; it primarily involves `p pi-p pi` bonds. - **Conclusion**: `SO3^(3-)` does not have `p pi-d pi` bonds. 7. **Analyze `HSO3^-`**: - In `HSO3^-`, sulfur forms three bonds with oxygen, but similar to `SO3^(3-)`, these are primarily `p pi-p pi` bonds. - **Conclusion**: `HSO3^-` does not have `p pi-d pi` bonds. ### Final Count: - The compounds that have `p pi-d pi` multiple bonds are: `SO2`, `SO3`, `HSO4^-`, and `SO4^(2-)`. - Therefore, **4 compounds** have `p pi-d pi` multiple bonds. ### Summary of Results: - (i) `SO2` - Yes - (ii) `SO3` - Yes - (iii) `HSO4^-` - Yes - (iv) `SO4^(2-)` - Yes - (v) `SO3^(3-)` - No - (vi) `HSO3^-` - No ### Total Compounds with `p pi-d pi`: **4**

To determine how many of the given compounds have `(p pi-d pi)` multiple bonds, we need to analyze each compound one by one. ### Step-by-Step Solution: 1. **Identify the Compounds**: We have the following compounds to analyze: - (i) `SO2` - (ii) `SO3` - (iii) `HSO4^-` ...
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