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Commet on the reactions of dihydrogen wi...

Commet on the reactions of dihydrogen with (a) chlorine,(b) sodium and (c) copper (II) oxide.

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dihydrogen reduces chlorine into chloride `(Cl^(ɵ))` ion and itself gets oxidised to `H^(o+)` ion by chlorine to form hydrogen chloride. An electron pair is shared between `H` and `Cl` leaving to the formation of a covalent molecule.
`H_(2g)+Cl_(2g)tounderset("Hydrogen chloride")(2HCl_(g))`
(b) Dihydrogen is reduced by sodium to form `NaH`. an electron is transfer from `Na` to `H` leading to the formation of an ionic compound, `Na^(o+)H^(ɵ)`.
red between `H` and `Cl` leaving to the formation of a covalent molecule.
`H_(2g)+2Na_(2g)tounderset("Sodium hydride")(2NaH_(s)`
(c) Dihydration reduces copper `(II)` oxide to copper in zero oxidation state and itself gets oxidised to `H_(2)O`, which is a covalent molecule.
`H_(2(g))+CuOtoCu_(s)+H_(2)O_((1))`
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