Home
Class 11
CHEMISTRY
100 mL sample of distilled water, tap wa...

`100 mL` sample of distilled water, tap water and boiled water required, respectively, `2 mL,17 mL` and `7 mL` of soap solution to form permanent lather. The ratio of permanent to temprorary hardness in the tap water is

A

`3:2`

B

`2:3`

C

`1:2`

D

`2:1`

Text Solution

Verified by Experts

The correct Answer is:
C

(c)
(Temprorary and permanent hardness) in tap `H_(2)O=15 mL`
Permanent in boiled `H_(2)O=5mL`
Temprorary hardness in `H_(2)O=15-5=10 mL`
`("Permanent hardness")/("Temporary hardness")=5/10=1:2`
Promotional Banner

Topper's Solved these Questions

  • HYDROGEN, WATER AND HYDROGEN PEROXIDE

    CENGAGE CHEMISTRY|Exercise Solved Examples|8 Videos
  • HYDROGEN, WATER AND HYDROGEN PEROXIDE

    CENGAGE CHEMISTRY|Exercise Ex 3.1|4 Videos
  • GENERAL ORGANIC CHEMISTRY

    CENGAGE CHEMISTRY|Exercise Analytical and Descriptive|1 Videos
  • IONIC EQUILIBRIUM

    CENGAGE CHEMISTRY|Exercise Archives Subjective|28 Videos

Similar Questions

Explore conceptually related problems

25mL samples of distiled water, tap water and boiled water required, respectively, 1mL, 13mL and 5mL of soap solution to form a permanent lather. The ratio of temporary to permanent hardness in the tap water is

100 mL of a sample of tap water requires 50 mL of N // 50- HCl solution for titration. Calculate the temporary hardness of tap water.

If 30 ml of H_2 and 20 ml of O_2 react to form water, what is left at the end of the reaction ?

0.5 g of an oxalate was dissolved in water and the solution made to 100 mL. On titration 10 mL of this solution required 15 mL of (N)/(20)KMnO_(4) . Calculate the percentage of oxalate in the sample .